The value of the car after 12 years is $15,229.50
Here, we want to calculate the value of a car that loses a percentage of its origial value after some years
To do this, we shall need an exponential equation that represents decay or depreciation
We can have this as;
![P=I(1-r)^t](https://img.qammunity.org/2023/formulas/mathematics/high-school/4k4pvb19m28y13dz9p22vzqluveyn94ctx.png)
where;
P is the present value that we want to calculate
I represents the original value of the car which is $32,000
r is the percentage of decrease per year
From the question, there is a decrease of 18% every 3 years
The percentage decrease per year will be 18%/3 = 6%
6% is same as 6/100 = 0.06
t represents the time frame we are considering = 12 years
We proceed to input all these values into the equation above
We have it as;
![\begin{gathered} P=32,000(1-0.06)^(12) \\ \\ P=32,000(0.94)^(12) \\ \\ P\text{ = \$15,229.50} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/qpa89f31utlmxp1de0cxve92d49rh93o9j.png)