Question

The perimeter of a rectangular garden is 252 feet. If the width of the garden is 53 feet , what is its length

Answer 1

The perimeter of a rectangle is given by:

`P=2l+2w`

Where:

P = perimeter = 252 ft

w = width = 5 ft

l = lenght

Then, substitute the values:

`252=2l+2(53)`

And solve for l:

`\begin{gathered} 252=2l+106 \\ 252-106=2l+106-106 \\ 146=2l \\ (146)/(2)=(2l)/(2) \\ l=73 \end{gathered}`

Answer: length = 73 ft