Question

Can you please help me

Answer 1

From the question,

`\begin{gathered} m\angle AFE=m\angle BFC\text{ (Vertically opposite angles)} \\ \therefore \\ m\angle AFE=70^(\circ) \end{gathered}`

We also have

`m\angle AFB=m\angle EFC\text{ (Vertically opposite angl}es)`

Remember that the sum of angles at a point equals 360°. Therefore

`\begin{gathered} m\angle AFB+m\angle BFC+m\angle CFE+m\angle AFE=360 \\ \therefore we\text{ have} \\ 2(m\angle AFB)+2(70)=360 \\ 2(m\angle AFB)=360-140=220 \\ m\angle AFB=(220)/(2)=110 \end{gathered}`

Therefore, m(AB) is 110°.

Hence, OPTION B is correct.