Question

If the area of a rectangular field is x2 – 3x + 4 units and the width is 2x – 3, then find the length of the rectangular field.x2- 3 x + 42 x − 3 unitsx2 - 3x + 4 units2x - 3 units3x + 4 units

Answer 1

We are given the following

`\begin{gathered} Area=x^2-3x+4 \\ \\ Width=2x-3 \\ \\ Length=? \end{gathered}`

Using the Area of a Rectangle we have

`\begin{gathered} Area=lw \\ \\ l=(A)/(w) \\ \\ l=(x^2-3x+4)/(2x-3) \end{gathered}`

Therefore, the answer is

`(x^(2)-3x+4)/(2x-3)units`