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The vertex of a quadratic function is (2, -1) and its y-intercept is 7. Find the function,

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Given:-


\text{vertex}=(2,-1),y-intercept=7

To find:-

The function.

So the formula is,


y=a\mleft(x-h\mright)^(2)+k

So substituting we get,


y=7(x-2)^2-1

So the value. we get,


\begin{gathered} y=7(x-2)^2-1 \\ y=7(x^2-4x+4)-1 \end{gathered}

Since the value of x is,


\begin{gathered} y=7x^2-28x+28-1 \\ y=7x^2-28x+27 \end{gathered}

So the value,


y=7x^2-28x+27

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