Question

The vertex of a quadratic function is (2, -1) and its y-intercept is 7. Find the function,

Answer 1

Given:-

`\text{vertex}=(2,-1),y-intercept=7`

To find:-

The function.

So the formula is,

`y=a\mleft(x-h\mright)^(2)+k`

So substituting we get,

`y=7(x-2)^2-1`

So the value. we get,

`\begin{gathered} y=7(x-2)^2-1 \\ y=7(x^2-4x+4)-1 \end{gathered}`

Since the value of x is,

`\begin{gathered} y=7x^2-28x+28-1 \\ y=7x^2-28x+27 \end{gathered}`

So the value,

`y=7x^2-28x+27`