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F(x) = square root of x - 5. find f^-1 (x) and it’s domain

User Sravanti
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1 Answer

4 votes

Given:

f(x) = root x - 5

Rewrite the function using y,


y=\sqrt[]{x}-5

Now, interchange the position of x and y in the function,


x=\sqrt[]{y}-5

Isolate the dependent variable


\begin{gathered} \sqrt[]{y}=x+5 \\ y=(x+5)^2 \end{gathered}

Therefore,


f^(-1)(x)=(x+5)^2

And the domain is minus infinity to infinity


\begin{gathered} f^(-1)(x)=(x+5)^2 \\ \text{Domain}=(-\infty,\infty) \end{gathered}

User Lars Kanis
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