Question

A kid is on a stationary sled, onsnowy ground with fls 0.105.It takes 71.2 N of force to setthe sled moving. How muchnormal force is acting?(Unit = N)

Answer 1

`678.10N`

Step-by-step explanation

Parameters given:

Coefficient of static friction, μs = 0.105

Force, F = 71.2 N

The minimum force required to set the sled moving must be equal to the frictional force acting on the sled.

The frictional force is given mathematically as:

`F_f=\mu_sN`

where N = normal force

Since the force required is equal to the frictional force, we have that:

`F=F_f`

Therefore:

`F=\mu_sN`

Solve for N:

`\begin{gathered} N=(F)/(\mu_s) \\ N=(71.2)/(0.105) \\ N=678.10N \end{gathered}`

That is the normal force.