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Suppose you know students at school are, on average, 68 inches tall with a standard deviation of 4 inches. If you sample 36 students, what is the probability their average height is more than 70 inches?

User Jaltiere
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Answer:

0.135% or 0.00135

Explanation:

• The population mean height = 68 inches

,

• The population standard deviation = 4 inches

,

• Sample Size, n = 36

First, find the sample standard deviation:


\sigma_x=(\sigma)/(√(n))=(4)/(√(36))=(4)/(6)=(2)/(3)

Next, for X=70, find the z-score:


\begin{gathered} z-score=(X-\mu)/(\sigma_x) \\ z=(70-68)/(2\/3)=(2)/(2\/3)=3 \end{gathered}

Since we are looking for the probability that their average height is more than 70 inches, we need to find:

• P(X>70)=P(z>3)

Using the z-score table:


P(z>3)=0.0013499

The probability that their average height is more than 70 inches is 0.135%.

User NstCactus
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