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If AACB = ADCE, ZCAB = 63°,ZECD = 52°, and ZDEC = 5xDE(c сx = [?]

If AACB = ADCE, ZCAB = 63°,ZECD = 52°, and ZDEC = 5xDE(c сx = [?]-example-1

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Since angles ACB and ECD are vertical angles, they are congruent, so we have

Calculating the sum of internal angles in triangle ABC, we have:


\begin{gathered} ABC+ACB+CAB=180 \\ ABC+52+63=180 \\ ABC=180-52-63 \\ ABC=65 \end{gathered}

Since triangles ACB and DCE are congruent, we have
\begin{gathered} DEC=ABC \\ 5x=65 \\ x=13 \end{gathered}

User Al Sweetman
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