Question

2: A game is played by tossing a single coin onto a square table. The square is 25 inches o each side, and the coin has a radius of 10 inches (it's old fashioned). If the coin lands entirely on the table (nothing hanging off the edge), the player wins a prize. What fraction of the table can the center point of the coin land on so that the player wins a prize?

Answer 1

Find the area of the square table:

`\text{Area of the square = }L^2=25^2=625in^2`

Find the area of the coin (area of a circle):

`\text{Area of coin= }\pi r^2=\pi10^2=314.16in^2`

To find the fraction of the table the center point of the coin lands, we have:

`\frac{Area\text{ of coin}}{\text{Area of table}}`
`=(314.16)/(625)\text{ = }0.50`

Since we are to leave the answer in fraction, we have:

`(5)/(10)=\text{ }(1)/(2)`