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In which quadrant does 0 lie if the following statements are true:sin 0 > 0 and sec 0 < 0Quadrant IQuadrant IIQuadrant IIIQuadrant IV

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\begin{gathered} \sin \theta=(y)/(r) \\ \sec \theta=(r)/(x) \end{gathered}

Given the conditions in the question:

1. sin θ > 0, therefore, it must be positive. From that, we can conclude that y must be on the positive side, therefore, located at the top of the coordinate plane.

2. sec θ < 0, therefore, it must be negative. From that, we can conclude that x must be on the negative side, therefore, located at the left side of the coordinate plane.

Therefore, the quadrant that the θ belongs to is in the top and left of the coordinate plane and that is Quadrant II.

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