234k views
2 votes
Determine the equation of the graphed circleReminder that the equation should look like the example I provided

Determine the equation of the graphed circleReminder that the equation should look-example-1
Determine the equation of the graphed circleReminder that the equation should look-example-1
Determine the equation of the graphed circleReminder that the equation should look-example-2
User Rory Alsop
by
8.4k points

1 Answer

4 votes

The equation of a circle of radius r and center at (h, k) is:


(x-h)^2+(y-k)^2=r^2

The image provided shows a circle and we must find the radius and center by simple inspection.

The center is located at (-5, 3).

From that point, until I find a point of the circumference I can count 4 units. It is confirmed when I see the segment from (-9, 3) to (-1, 3) as a diameter of length 8. The radius is half the diameter, thus r = 4.

Substituting, we have the required equation:


\begin{gathered} (x+5)^2+(y-3)^2=4^2 \\ \boxed{\mleft(x+5\mright)^2+\mleft(y-3\mright)^2=16} \end{gathered}

User Leony
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories