The equation of a circle of radius r and center at (h, k) is:
![(x-h)^2+(y-k)^2=r^2](https://img.qammunity.org/2023/formulas/mathematics/college/5s77z5lwu6jnvb5vkwanu2jvhq5sh1qkc3.png)
The image provided shows a circle and we must find the radius and center by simple inspection.
The center is located at (-5, 3).
From that point, until I find a point of the circumference I can count 4 units. It is confirmed when I see the segment from (-9, 3) to (-1, 3) as a diameter of length 8. The radius is half the diameter, thus r = 4.
Substituting, we have the required equation:
![\begin{gathered} (x+5)^2+(y-3)^2=4^2 \\ \boxed{\mleft(x+5\mright)^2+\mleft(y-3\mright)^2=16} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/yjotcxyv08fj3kqk2z9dd5ciijp0hr06j5.png)