Given the equation system:
![\begin{gathered} 1)y=4x \\ 2)3x+2y=55 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/io9ngtbpq08bja51wqjgnmzn051kj5ebky.png)
The first step is to replace the first equation in the second equation
![3x+2(4x)=55](https://img.qammunity.org/2023/formulas/mathematics/college/cmpxxh3aa26skqj3z3bcy2gk7crjws6lsv.png)
With this, we have a one unknown equation. Now we can calculate the value of x:
![\begin{gathered} 3x+8x=55 \\ 11x=55 \\ (11x)/(11)=(55)/(11) \\ x=5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fkgm3f49exv53kja62p9tk2sorol77wyop.png)
Now that we know the value of x, we can determine the value of y, by replacing x=5 in the first equation
![\begin{gathered} y=4x \\ y=4\cdot5 \\ y=20 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/antu8lujkikiv88ppqbq9xld0tf665zymj.png)
This system has only one solution and that is (5,20)