As given that first 5grades are: 71%, 82%, 71%, 78% and 78%.
Let the 6th grade be C
a). Then:
![75\leq(71+82+71+78+78+C)/(6)\leq80](https://img.qammunity.org/2023/formulas/mathematics/college/mwgeghk4kj40zavjn5korbbvum1u48y3k4.png)
Simplifying it:
![\begin{gathered} 75\leq(71+82+71+78+78+C)/(6) \\ 75*6\leq380+C \\ 450\leq380+C \\ 450-380\leq C \\ 70\leq C \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1ki3ga75gimqwz74p5dvszhs52eces6zu7.png)
And:
![\begin{gathered} (380+C)/(6)\leq80 \\ 380+C\leq480 \\ C\leq100 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4gox9xy0hf2300rxtwwtlhri9d5tm1h81u.png)
So C should be in between 70 to 100.
b). For at least 80%:
![\begin{gathered} (71+82+71+78+78+C)/(6)\ge80 \\ 380+C\ge80*6 \\ 380+C\ge480 \\ C\ge100 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/8knvyzofevtsfyy68ok10akmkj6j9qq1rq.png)
It is not possible for getting b grade as one cannot achieve more than maximum marks if the maximum marks are 100.