Question

Solve by using quadratic formula25c^2 + 40c + 16= 0

Answer 1

Recall that the quadratic formula states that the solutions to the equation:

`ax^2+bx+c=0`

are:

`x=(-b\pm√(b^2-4ac))/(2a).`

Therefore the solutions to the given equation are:

`c=(-40\pm√(40^2-4(25)(16)))/(2(25)).`

Simplifying the above result we get:

`c=(-40\pm√(1600-1600))/(2(25))=(-40)/(50)=-(4)/(5)`

Answer: The given equation has only one solution:

`-(4)/(5).`