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If n(B) = 16, n(A ∪ B) = 26, and n(A ∩ B) = 5, find n(A).

User Steaphann
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1 Answer

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19 votes

Answer: 15

Work Shown:


n(A \cup B) = n(A) + n(B) - n(A \cap B)\\\\26 = n(A) + 16 - 5\\\\26 = n(A) + 11\\\\n(A) + 11 = 26\\\\n(A) = 26-11\\\\n(A) = 15\\\\

User Temi
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