274,526 views
37 votes
37 votes
If n(B) = 16, n(A ∪ B) = 26, and n(A ∩ B) = 5, find n(A).

User Steaphann
by
3.5k points

1 Answer

19 votes
19 votes

Answer: 15

Work Shown:


n(A \cup B) = n(A) + n(B) - n(A \cap B)\\\\26 = n(A) + 16 - 5\\\\26 = n(A) + 11\\\\n(A) + 11 = 26\\\\n(A) = 26-11\\\\n(A) = 15\\\\

User Temi
by
2.7k points