Question

The velocity of a wagon increases from 3 m/s to 9 m/s as it

accelerates uniformly down a hill. The average velocity of the
wagon is
m/s.

Answer 1

6 m/s

Step-by-step explanation:

The equation that relates time, distance, and acceleration is:

a = (vf - vi)/t

where a is acceleration (m/s^2), time is time (seconds) and vf and vi are the initial (vi) and final (vf) velocities (m/s).

Average velocity is (vf + vi)/2

We are given that:

vi = 3 m/s

vf = 9 m/s

Average velocity for the wagon is thus:

is (9 + 3)/2 = 6 m/s