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AB. CD. EF are three chords of a circle, P and Q are two points inside the circle such that AB and CD meet at P, and AB and EF meet at Q. If CP = 2, PD = 7, EQ = 3, QF = 6 and AP = 2, then QB may be A.
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AB. CD. EF are three chords of a circle, P and Q are two points inside the circle such that AB and CD meet at P, and AB and EF meet at Q. If CP = 2, PD = 7, EQ = 3, QF = 6 and

AP = 2, then QB may be
A. 2 B. 3 C. 4 D. 5 E. 7​

User Frank Dejay
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1 Answer

3 votes

Answer:

Explanation:

I think it is option E) 7

User Yan Koshelev
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