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2 votes
Find a polynomial function of lowest degree with rational coefficients that has the

given numbers as some of its zeros.
√3,51
The polynomial function in expanded form is f(x) =

User Curtis
by
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1 Answer

2 votes

Answer:
f(x)=x^3 -51x^2 -3x+153

Explanation:

By the conjugate root theorem, the roots are
√(3), -√(3), 51.

Letting the leading coefficient be 1,


f(x)=(x-√(3))(x+√(3))(x-51)\\\\=(x^2 -3)(x-51)\\\\=x^3 -51x^2 -3x+153

User Jholloman
by
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