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For which value of x does the graph of the following function F(x) have a

vertical asymptote?
F(x) =
1
X-11

User Esilik
by
3.4k points

1 Answer

2 votes

Answer:

x = 1

Explanation:

Horizontal asymptotes are the y-values for which a particular function is undefined;

Finding the horizontal asymptote for linear reciprocal function is quite simple;

For this kind of function, where there is no x term in the numerator, the horizontal asymptote is just equivalent to the constant added to the fraction (note: having no added constant is the same as having an added 0);

so:

f(x) = 1/(x - 1) = (1/( - 1 )) + 0

The horizontal asymptote is y = 0 for this function.

If it was F(x) = (1/(x - 1)) + 1, the horizontal asymptote would be y = 1

hope it help!! :)

User WY Hsu
by
3.7k points