Question

What is the mass in grams of 23.4 moles of NaCl?

Answer 1

1368.9 [gr].

Step-by-step explanation:

1. the formula of the required mass is:

m=Mν, where M=[gr/mol] and ν=[moles];

2. M=M(NaCl)=M(Na)+M(Cl)=23+35.5=58.5 [gr/mol];

ν=23.4 [moles] according to the condition, then

3. the required mass:

m=23.4*58.5=1368.9 [gr].