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40 votes
40 votes
How many different four-digit numbers can be formed with the numbers 7; 4; 5; 1; 2; 9; and 8?

User Eburgos
by
3.1k points

2 Answers

5 votes
5 votes

Answer:

2 answers.

Explanation:

ANSWER 1: With Repetition

Numbers: 1,2,4,5,7,8

There are 4 digits __ __ __ __

1st digit can be filled by any of the 6 numbers.

Similarly 2nd, 3rd and 4th digits.

Hence each digit will have 6 possibilities.

Therefore no.of 4 digit numbers that can be formed are 6 x 6 x 6 x 6 = 1296

ANSWER 2: Without Repetition

4 digits __ __ __ __

Now the first digit can be filled by any of the six numbers. Therefore there are 6 possibilities

The second digit will have only 5 possibilities as one of the numbers gets used up by the 1st digit.

Similarly the 3rd and 4th digits will have 4 and 3 possibilities respectively.

Therefore no.of 4 digit numbers that can be formed are 6 x 5 x 4 x 3 = 360

User YulkyTulky
by
2.9k points
13 votes
13 votes

Answer:

I believe it's 2401.

Explanation:

7 x 7 x 7 x 7 = 2401

User Wes Field
by
2.5k points