35.7k views
5 votes
Two people walk from different parts of the city to meet each other. When they meet, they figure out that one of them walked a quarter of the way plus 0.6 km. The other person walked twice as far. How far apart were the people originally?

User OldTroll
by
8.3k points

2 Answers

2 votes

Answer:

7.2km

Explanation:

User Ericharlow
by
7.6k points
4 votes

Answer:

They were 7.2 km apart originally

Explanation:

Let the original distance separating the two people be x

One person walked quarter of this distance + 0.6

=> x/4 + 0.6

The other person walked twice this distance

=> 2 (x /4 + 0.6) = x/2 + 1.2

Since they meet at a common point along the way, the sum of the distances covered = original distance

=> x/4 + 0.6 + x/2 + 1.2 = x

=> 3x/4 + 1.8 = x

=> x = 3x/4 + 1.8

=> x - 3x/4 = 1.8

=> 1x/4 = 1.8

=> x = 1.8 x 4 = 7.2 km

Check:
Person 1 walked 7.2/4 + 0.6 = 1.8+0.6 = 2.4

The other person walked twice as far = 2 x 2.4 = 4.8

2.4 + 4.8 = 7.2

User Eythort
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories