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Elsa, Chau, and Felipe served a total of 100 orders Monday at the school cafeteria. Chau served 3 times as many orders as Felipe. Felipe served 5 more orders than Elsa. How many orders did they each serve?

User Tommy  Yu
by
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2 Answers

6 votes

Let us assume that,

→ Elsa = x

→ Felipe = x + 5

→ Chau = 3x + 15

Now the required value of x,

→ x + x + 5 + 3x + 15 = 100

→ 5x + 20 = 100

→ 5x = 100 - 20

→ x = 80/5

→ [ x = 16 ]

Then the orders each serve is,

→ Elsa = x = 16

→ Felipe = x + 5 = 16 + 5 = 21

→ Chau = 3x + 15 = 48 + 15 = 63

Hence, the above one is correct.

User Matthew Shearer
by
7.6k points
3 votes

Answer:

Chau served 63 orders.

Elsa served 16 orders.

Felipe served 21 orders.

Explanation:

Given information:

  • Elsa, Chau, and Felipe served a total of 100 orders.
  • Chau served 3 times as many orders as Felipe.
  • Felipe served 5 more orders than Elsa.

Define the variables:

  • Let e = number of ordered Elsa served.
  • Let c = number of ordered Chau served.
  • Let f = number of ordered Felipe served.

Create a system of equations from the given information and defined variables:


\begin{cases}e+c+f=100\\c=3f\\e=f-5\end{cases}

Substitute the second and third equations into the first equation and solve for f:


\implies e+c+f=100


\implies (f-5)+3f+f=100


\implies 5f-5=100


\implies 5f=105


\implies f=21

Substitute the found value of f into the second equation and solve for c:


\implies c=3f


\implies c=3(21)


\implies c=63

Substitute the found value of f into the third equation and solve for e:


\implies e=f-5


\implies e=21-5


\implies e=16

Therefore:

  • Chau served 63 orders.
  • Elsa served 16 orders.
  • Felipe served 21 orders.
User Prabaha
by
7.8k points
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