Question

Elsa, Chau, and Felipe served a total of 100 orders Monday at the school cafeteria. Chau served 3 times as many orders as Felipe. Felipe served 5 more orders than Elsa. How many orders did they each serve?

Answer 1

Let us assume that,

→ Elsa = x

→ Felipe = x + 5

→ Chau = 3x + 15

Now the required value of x,

→ x + x + 5 + 3x + 15 = 100

→ 5x + 20 = 100

→ 5x = 100 - 20

→ x = 80/5

→ [ x = 16 ]

Then the orders each serve is,

→ Elsa = x = 16

→ Felipe = x + 5 = 16 + 5 = 21

→ Chau = 3x + 15 = 48 + 15 = 63

Hence, the above one is correct.

Answer 2

Chau served 63 orders.

Elsa served 16 orders.

Felipe served 21 orders.

Explanation:

Given information:

• Elsa, Chau, and Felipe served a total of 100 orders.
• Chau served 3 times as many orders as Felipe.
• Felipe served 5 more orders than Elsa.

Define the variables:

• Let e = number of ordered Elsa served.
• Let c = number of ordered Chau served.
• Let f = number of ordered Felipe served.

Create a system of equations from the given information and defined variables:

`\begin{cases}e+c+f=100\\c=3f\\e=f-5\end{cases}`

Substitute the second and third equations into the first equation and solve for f:

`\implies e+c+f=100`

`\implies (f-5)+3f+f=100`

`\implies 5f-5=100`

`\implies 5f=105`

`\implies f=21`

Substitute the found value of f into the second equation and solve for c:

`\implies c=3f`

`\implies c=3(21)`

`\implies c=63`

Substitute the found value of f into the third equation and solve for e:

`\implies e=f-5`

`\implies e=21-5`

`\implies e=16`

Therefore:

• Chau served 63 orders.
• Elsa served 16 orders.
• Felipe served 21 orders.