Question

Which value of y makes the inequality 3y^2+2(y-5)>8 true?

A. y = 0
B. y = –1
C. y = –2
D. y = –3

Answer 1

The answer is D
you substitute each of the values into y

3(-3)^2+2(-3-5)>8

you square the -3 and then multiply by 3, you’re left with 27+2(-3-5)>8

You then subtract -3-5 inside the parentheses and are left with 27+2(-8)>8 multiply the 2 and -8
27+(-16)>8 or 27-16>8
Subtract and you’re left with 11>8
All the others are the same steps, but they are not true