Alr so i did this a while back so i’m not sure how accurate this is, but i definitely tried my best. Let the final steady temperature = 0
The copper cools from 100 °C to 0
The aluminium and spirit both warm up from 10.0 °C to 0 Proceeding as in the previous examples, remembering to work in kg,
Heat in J given out by copper
Heat in J received by aluminium
Heat in J received by spirit
= 0.25 x 400 x (1000)
= 0.01 × 900 x (0-10)
= 0.12 × 2400 × (0 10)
Heat given out = heat received
therefore
100 (1000) = 9 × (010) + 288 × (0 10)
or,
10 000 100 0 297 0 2970 - =
12 970 397 0
12970
0 =
=
12.970
397
= 32.7 °C
Rearranging,
whence