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What are the coordinates of the point on the directed line segment from (-5,3) to (5,8) that partitions the segment into a ratio of 3 to 2?

User Hemmer
by
7.8k points

2 Answers

5 votes

Answer:

1,6

Explanation:

From -5 to +5 (for x) is 10 we need 3/ ( 2+3) ths of this = 6

-5 + 6 = 1

for y from 3 to 8 is 5 we need 3/5ths of this = 3 added to 3 = 6

User Malbarbo
by
8.3k points
3 votes

Answer:

(1, 6)

Explanation:

Definitions:

  • Let A = (-5, 3)
  • Let B = (5, 8)
  • Let M be the required point.

Given ratio 3 : 2.

Therefore, point M is ³/₅ along the line from point A to point B.


\begin{aligned}\implies x_M&=(3)/(5)(x_B-x_A)+x_A\\&=(3)/(5)(5-(-5))+(-5)\\&=(3)/(5)(10)-5\\&=1\end{aligned}


\begin{aligned}\implies y_M&=(3)/(5)(y_B-y_A)+y_A\\&=(3)/(5)(8-3)+3\\&=(3)/(5)(5)+3\\&=6\end{aligned}

Therefore, point M is (1, 6).

What are the coordinates of the point on the directed line segment from (-5,3) to-example-1
User Sia
by
8.1k points

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