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4 votes
A frog leaps from flat ground at 6.32 m/s

at a 36.3 angle. What maximum height
does it reach?
(Unit = s)

1 Answer

5 votes

At hmax, Vy=0

vy=v0y-gt

0=6.32sin(36.3)-9.81t

t=.381 seconds

Δy=v0yt-.5gt^2

Δy=6.32sin(36.3)*.381-.5(9.81)(.381)^2

maximum height=.714 m

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