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A paper company is designing a new, pyramid-shaped paperweight. Its development team has decided

that to make the width of the paperweight 4 inches less than the length and the height of the
paperweight 3 inches less than the length. The paperweight must have a volume of 12 cubic inches.
What are the dimensions of the paperweight?
The width is
inches, the length is
inches, and the height is
inches

User Guerry
by
7.8k points

2 Answers

6 votes

Final answer:

To find the dimensions of the pyramid-shaped paperweight with a given volume of 12 cubic inches, you need to solve for the length using the formula for the volume of a rectangular pyramid, and from there, calculate the width and height as they are defined relative to the length.

Step-by-step explanation:

The student's question requires solving for the dimensions of a pyramid-shaped paperweight given its volume and the relationship between its length, width, and height. Since the paper company team has decided that the width of the paperweight is 4 inches less than the length (L) and the height of the paperweight is 3 inches less than the length, we can represent the width as (L - 4) inches and the height as (L - 3) inches. The volume of a rectangular pyramid is given by the formula V = (1/3) x length x width x height.

Given the volume (V) is 12 cubic inches, we can set up the equation:

12 = (1/3) x L x (L - 4) x (L - 3)

By solving this equation, we find the dimensions that satisfy the volume requirement for the paperweight.

User Andrei Bularca
by
7.6k points
3 votes

Answer:

4x+3=12

Step-by-step explanation:

User Inigomedina
by
6.6k points