Answer:
The species that oxidizes is lithium, or Li
Step-by-step explanation:
Since I2 is know to be a halogen, and halogens are oxidizers, iodine is probably not the species being oxidized. So, Li is being oxidized.
Another way to look at the problem is to assign oxidation numbers to all elements on the right and left
The left:
lithium = 0
iodine = 0
Both are 0 since they are in their most stable elemental states
The right:
lithium : +1
Iodine: -1
When something looses an electron and becomes more positive, it is oxidized. Lithium goes from 0 to 1, clearly displaying a rise in oxidization state. So, lithium is being oxidized.