Question

A store owner mixes 2 lbs of candy that cost x dollars pound with 3 lb of candy that costs $1.50 per pound. she sells the mix for $2.50 per pound. how much did the 3lb of the second type cost the owner?

Answer 1

Algebraic equations are mathematical equations that consist of unknown variables. These unknown variables can be represented with any letter of the alphabet.

The cost of 2 pounds(lb) of the first type of candy is $8

Note that: x represents the cost per pound (lb) of the first type of candy

The Algebraic equation for the above statement is given as:

2lb × $x + 3 Ib × $1.50 = $2.50(2lb + 3lb)

2x + 4.5 = 12.5

Collect like terms

2x = 12.5 - 4.5

2x = 8

Divide both sides by 2

2x/2 = 8/2

x = 4

The cost of the 1 pound of first type of candy is $4

The cost of 2 pounds(lb) of the first type of candy is calculated as:

2 x $4

= $8

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