Question

A sand bag is dropped from a hot air balloon. It reached the ground 13 seconds later. What was the final velocity of the sand bag? (neglect air resistance)

a=
vf=
vi=
t=

Answer 1

V = 127.4 m/s

Step-by-step explanation:

Using the following expression:

V = V₀ + a * t

Applying to vertical movement:

V = 0 + g * t (Start at rest and a = g = 9.8 m/s²)

V = g * t

V = 9.8 * (13)

V = 127.4 m/s