Register

Calculate the magnitude of the repulsive force between a +500μC charge and a +100μC charge which are 5 m apart. [k=9×109 Nm2C-1]

Calculate the magnitude of the repulsive force between a +500μC charge and a +100μC charge which are 5 m apart. [k=9×109 Nm2C-1]
156k views
3 votes
Calculate the magnitude of the repulsive force between a +500μC charge and a +100μC charge which are 5 m apart. [k=9×109 Nm2C-1]

User Alexey Korsun
by
7.5k points

1 Answer

6 votes
Fe=kq1q2/r
(9x10^9)(500x10^-6)(100x10^-6)/(5)
(450)/(5)
90 Newtons
User Baptiste Donaux
by
8.6k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

At sea level, water boils at 100 degrees celcius and methane  boiled at -161 degrees celcius. Which of these substances has a stronger force of attraction between its particles? Explain your answer
Physical properties of minerals graphic organizer
A snowball is launched horizontally from the top of a building at v = 16.9 m/s. If it lands d = 44 meters from the bottom, how high (in m) was the building?
Link Copied!