Question

The minimum value of Y in the equation y = x2 - 6x + 8

Answer 1

Given

`y=x^2-6x+8`

To obtain the minimum value of y, we first take the derivative of y

The derivative of y is:

`y^(\prime)=2x-6`

Equating

`y^(\prime)\text{ = 0}`

gives the minimum value we require.

Doing that, we have:

`2x-6=0`

So that

`\begin{gathered} 2x=6 \\ x=(6)/(2) \\ =3 \end{gathered}`

Therefore, the minimum value is x = 3