Question

What is the total amount of heat needed to change 31g of silver at 0.0°C to 1°C? The specific heat of silver is 0.129 J/g∙°C

Answer 1

Step-by-step explanation

o solve this , we need to use the formula:

`\begin{gathered} Q=m*c*(T_f-T_0) \\ where \\ m\text{ is the mass measured in kg} \\ c\text{ is the specific heat of silver=0.129 J/\degree C} \\ T_f\text{ and T}_o\text{ are the final and initial temperatures} \end{gathered}`

so

Step 1

) Let

`mass=31\text{ gr}`

so, we need to convert from grams to kilograms ,to do that, divide the amount in grams by 1000

so

`mass_(kg)=(31)/(1000)=0.031\text{ kg}`

and

`\begin{gathered} T_f=\text{1\degree C} \\ T_0=0°\text{ C} \end{gathered}`

b) now, replace in the formula

`\begin{gathered} Q=mc(T_(f)-T_(0)) \\ Q=0.031gr*0.129(J)/(g°C)(1°C-0°C) \\ Q=0.003999\text{ Joules} \end{gathered}`

so, the answer is 0.003999 Joules

hope this helps you