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Find the equation (in terms of x ) of the line through the points (-2,-2) and (3,-1)

User Dtldarek
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1 Answer

4 votes

Answer:

Equation of line is given as y = mx + c, where m is the gradient and c is the y-intercept.

First find the gradient.

Formula of gradient is given as (y2-y1)÷(x2-x1) or (y1-y2)÷(x1-x2)

Gradient = (-1-(-2))÷(3-(-2))

= (-1+2)÷(3+2)

= 1/5

Equation is y = 1/5 + c

Substitute either one of the points into the equation to find c.

-2 = 1/5(-2) + c

c = -8/5

Hence equation of the line is y = 1/5x - 8/5

User Bodzio
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