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Help me please!!!!!!11!

Help me please!!!!!!11!-example-1
User Ketankk
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1 Answer

3 votes

Answer:


y=x^2-4x-2

Explanation:

Standard Form of Quadratic:


y=ax^2+bx+c

Vertex Form of Quadratic:


y=a(x-h)^2+k

h = vertex x

k = vertex y

Think of h and k as the ordered pair (h,k).

Match this ordered pair to the vertex ordered pair.

(h,k) = (2, -6)

Plug in (h,k) into vertex form:


y = a(x-2)^2-6

Use other point to solve for a.


3 = a(5-2)^2-6


3=a(3)^2-6


3=9a-6


9=9a


a=1

Plug a back into vertex form and expand the expression into standard form:


y=(x-2)^2-6


y=(x-2)(x-2)-6

Use F.O.I.L. method to expand (x-2)(x-2).

F(first):
x*x=x^2

O(outer):
x*-2=-2x

I(inner):
-2*x =-2x

L(last):
-2*-2=4


y=x^2-2x-2x+4-6

Combine like terms:


y=x^2-4x-2

User Incutonez
by
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