Question

A²-ab-ac+bc / a² +ab-ac-bc Simplying Algebraic fractions by factorizing​

Answer 1

(a - b)/(a + b).

Explanation:

a²-ab-ac+bc / a² +ab-ac-bc

= a(a - b) - c(a - b) / a(a + b) - c(a + b)

= (a - c)(a - b) / (a - c)(a + b)

The (a - c) is common to top and bottom, so

= (a - b)/(a + b).