Question

What is the equation of the line that passes through the point (3,−5) and has a slope of 0?

Answer 1

Slope zero
Y=0x+b
Y=b
Y=-5

Answer 2

The answer is y + 5 = 0

Explanation:

We know that, the equation of a line passing through point P(a, b) and slope m is given by

(y – b) = m(x – a) ...(1)

Here, The given point is P(3, -5) and slope is m = 0

from (1) we get

[(y – (-5)] = 0(x – 3)

y + 5 = 0 is the required equation of line.

Thus, The answer is y + 5 = 0

-TheUnknownScientist 72