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Prove that (2n + 3)²-(2n- 3)2 is a multiple of 8 for all positive integer values of n.​

User DAA
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1 Answer

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Answer:

The expression simplifies to 8(3n), a multiple of 8.

Explanation:

For integer values of n, you want to prove that (2n + 3)² - (2n - 3)² is a multiple of 8.

Simplify

The given expression is the difference of squares. It can be simplified to the product ...

(2n + 3)²- (2n - 3)² = ((2n + 3) - (2n - 3))×((2n + 3) + (2n - 3))

= (2n +3 -2n +3)(2n +3 +2n -3)

= 6(4n) = 24n = 8(3n)

For any integer n, the given expression will be a multiple of 8.

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Additional comment

It will also be a multiple of 2, 3, 4, 6, 12, and 24, as well as n.

User Dominik Seemayr
by
8.2k points

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