Question

Luke throws a fair coin n times

Find an expression, in terms of n, for the probability that Luke gets at least 1 head and at least 1 tail. ​

Answer 1

`(n^(2) )/(4)`

Explanation:

We know that the coin has 2 sides, which is tails and heads.

the total number of options is 2. whereas if tails or heads, 1 options

For tails:

`((1)/(2)) *n`

`(n)/(2)`

For heads:

`((1)/(2) ) * n`

`(n)/(2)`

If he does this in a row and expects 1 head and tail:

`(n)/(2) * (n)/(2)`

`(n^(2) )/(4)`