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What is the mass of 7.4 x 10^15 atoms of nickel (Ni)?

User Platalea Minor
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1 Answer

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Answer: 7.21 × 10⁻⁷ g

Step-by-step explanation:

Since we are starting from the number of atoms of Nickel, we need to know two sets of formulas:

mass = moles × molar mass

moles = atoms ÷ Avogadro's Number

⇒ mass = (atoms ÷ Avogadro's Number) × molar mass

mass = [(7.4 × 10¹⁵ atoms) ÷ (6.022 × 10²³ atoms/mole)] × (58.69 g/mol)

= 7.21 × 10⁻⁷ g

The mass of 7.4 x 10^15 atoms of nickel (Ni) is 7.21 × 10⁻⁷ g.

User Nicholas Muir
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