Question

Write an

equation for the line parallel to the given line that contains C.
C(1,6); y = - 4x + 1

Answer 1

Equation of line is given as y=mx+c, where m is gradient and c is the y-intercept.

Parallel lines have the same gradient so gradient = -4

Eqn: y = - 4x + c

Since the line passes through C(1,6), subt the coordinates into the equation to find y-intercept.

6 = -4(1) + c

c = 6+4 = 10

Hence, the equation of the line is y = - 4x + 10

Answer 2

y = -4x + 10

Explanation:

Parallel lines have the same slope

The line equation given is y = -4x + 1
Slope of this line is -4

A parallel line will also have slope = -4
So its equation will be y = -4x +b where b is the y-intercept

Substituting the coordinates for point C(x = 1, y = 6)

==> 6 = -4(1) + b

==> 6 = -4 + b

b = 10

So the equation of the parallel line is y = -4x + 10