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A hotel purchases a large photo for its newly renovated lobby. The perimeter of the photo is 290 in. The width is 5 in. more than three times the height. Find the dimensions of the photo.

User Tyronomo
by
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1 Answer

3 votes

Answer:

height = 35"

width = 110"

Explanation:

A hotel purchases a large photo for its newly renovated lobby. The perimeter of the photo is 290 in. The width is 5 in. more than three times the height. Find the dimensions of the photo.

height = h

w = 3h + 5"

perimeter = 2h + 2w

so:

2h + 2(3h+5) = 290

2h + 6h + 10 = 290

subtract 10 from both sides:

2h + 6h + 10 -10 = 290 - 10

2h + 6h = 280

combine left side:

8h = 280

divide by 8:

8h/8 = 280/8

h = 35"

So:

height = h = 35"

width = 3(35) + 5 = 110"

check:

perimeter = 2h + 2w

= 2(35) + 2(110)

= 70 + 220

= 290"

User Bhdrk
by
3.2k points