Answer:
B and D.
Explanation:
The first one is B x^2 + 2x + 1
As when x = 0, we have (0^2 + 2(0) + 1 = 1
and when x = 1 we have 1^2 + 2 + 1 = 4
the other values of x, 2 and 3 also fit this function.
The second one is D (x + 1)^2
because (x + 1)^2 = x^2 + 2x + 1.