Question

If p(x)=4(x2−5)+12, what is the value of p(11)?

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Answer 1

476

Explanation:

The equation is
p(x)=4(x²−5)+12

p(11) = 4(11² -5) + 12

= 4(121-5) + 12

= 4 x 116 + 12

= 464 + 12

= 476

Simplifying
⇒ p(x) = 4x² - 4 x 5 + 12

⇒ p(x) = 4x² - 20 + 12

⇒ p(x) = 4x² - 8

p(11) = 4 x 11² + 12